What is expand (f\circ g)2(-2x+1)^2-5(-2x+1) ?

The solution to expand (f\circ g)2(-2x+1)^2-5(-2x+1) is 8\circ fgx^2-8\circ fgx+2\circ fg+10x-5

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expand (f\circ g)2(-2x+1)^2-5(-2x+1)

expand

(f \circ g) 2 (- 2 x + 1)^{2} - 5 (- 2 x + 1)

8 \circ f g x^{2} - 8 \circ f gx + 2 \circ f g + 10 x - 5

Solution steps

(f \circ g) \cdot 2 (- 2 x + 1)^{2} - 5 (- 2 x + 1)

= 2 (\circ f g) (- 2 x + 1)^{2} - 5 (- 2 x + 1)

Expand

- 5 (- 2 x + 1) : 10 x - 5

= (f \circ g) \cdot 2 (- 2 x + 1)^{2} + 10 x - 5

Simplify

(f \circ g) \cdot 2 (- 2 x + 1)^{2} + 10 x - 5 : 8 \circ f g x^{2} - 8 \circ f gx + 2 \circ f g + 10 x - 5

= 8 \circ f g x^{2} - 8 \circ f gx + 2 \circ f g + 10 x - 5

(4 - 4 cos (x))^{2}

\frac{( x - 3 ) ^{2}}{25}

\frac{( x + 2 ) ( x - 4 )}{( x - 2 ) ( x - 6 )}

(a^{\frac{1}{2}} + b^{\frac{1}{2}})^{2}

(0.5 \cdot \frac{1}{3} + \frac{1}{5}) \cdot 1.2

What is expand (f\circ g)2(-2x+1)^2-5(-2x+1) ?
The solution to expand (f\circ g)2(-2x+1)^2-5(-2x+1) is 8\circ fgx^2-8\circ fgx+2\circ fg+10x-5