What is expand ((3-x)^3)/3 ?

The solution to expand ((3-x)^3)/3 is -(x^3)/3+3x^2-9x+9

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expand ((3-x)^3)/3

expand

\frac{( 3 - x ) ^{3}}{3}

- \frac{x ^{3}}{3} + 3 x^{2} - 9 x + 9

Solution steps

\frac{( 3 - x ) ^{3}}{3}

(3 - x)^{3} = 27 - 27 x + 9 x^{2} - x^{3}

= \frac{27 - 27 x + 9 x ^{2} - x ^{3}}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{27 - 27 x + 9 x ^{2} - x ^{3}}{3} = \frac{27}{3} - \frac{27 x}{3} + \frac{9 x ^{2}}{3} - \frac{x ^{3}}{3}

= \frac{27}{3} - \frac{27 x}{3} + \frac{9 x ^{2}}{3} - \frac{x ^{3}}{3}

Divide the numbers:

\frac{27}{3} = 9

= 9 - 9 x + \frac{9 x ^{2}}{3} - \frac{x ^{3}}{3}

Divide the numbers:

\frac{9}{3} = 3

= 9 - 9 x + 3 x^{2} - \frac{x ^{3}}{3}

Rewrite in standard form

= - \frac{x ^{3}}{3} + 3 x^{2} - 9 x + 9

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2^{x} ln (2) (x + 1)

What is expand ((3-x)^3)/3 ?
The solution to expand ((3-x)^3)/3 is -(x^3)/3+3x^2-9x+9