What is expand 1/((x+1)(x+2)(x+3)) ?

The solution to expand 1/((x+1)(x+2)(x+3)) is 1/(x^3+6x^2+11x+6)

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expand 1/((x+1)(x+2)(x+3))

expand

\frac{1}{( x + 1 ) ( x + 2 ) ( x + 3 )}

\frac{1}{x ^{3} + 6 x ^{2} + 11 x + 6}

Solution steps

\frac{1}{( x + 1 ) ( x + 2 ) ( x + 3 )}

Expand

(x + 1) (x + 2) (x + 3) : x^{3} + 6 x^{2} + 11 x + 6

= \frac{1}{x ^{3} + 6 x ^{2} + 11 x + 6}

(z + 2 i)^{2}

(2 x + \frac{1}{3})^{3}

(cos^{2} (x) + sec^{2} (x)) (cos^{2} (x) - 2)

\frac{( x ^{2} - 1 ) ^{4}}{4}

\frac{1}{x ( x - a ) ^{2}}

What is expand 1/((x+1)(x+2)(x+3)) ?
The solution to expand 1/((x+1)(x+2)(x+3)) is 1/(x^3+6x^2+11x+6)