What is expand (13x+6)/((x+1)(x-1)) ?

The solution to expand (13x+6)/((x+1)(x-1)) is (13x+6)/(x^2-1)

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expand (13x+6)/((x+1)(x-1))

expand

\frac{13 x + 6}{( x + 1 ) ( x - 1 )}

\frac{13 x + 6}{x ^{2} - 1}

Solution steps

\frac{13 x + 6}{( x + 1 ) ( x - 1 )}

Expand

(x + 1) (x - 1) : x^{2} - 1

= \frac{13 x + 6}{x ^{2} - 1}

(\frac{1}{x} + x) \cdot (1 - \frac{1}{x + 1})

\frac{\partial}{\partial x} ((z) (x^{2} + 3 x y - y^{2}))

sin (a) (1 - cos (b)) + sin (b) (1 - cos (a))

(3 x - 4 y + 4 = 0,) (9 x - 12 y - 4 = 0)

2 (3 + 5)

What is expand (13x+6)/((x+1)(x-1)) ?
The solution to expand (13x+6)/((x+1)(x-1)) is (13x+6)/(x^2-1)