What is expand (n(n+1)(n+2))/3 ?

The solution to expand (n(n+1)(n+2))/3 is (n^3)/3+n^2+(2n)/3

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expand (n(n+1)(n+2))/3

expand

\frac{n ( n + 1 ) ( n + 2 )}{3}

\frac{n ^{3}}{3} + n^{2} + \frac{2 n}{3}

Solution steps

\frac{n ( n + 1 ) ( n + 2 )}{3}

Expand

n (n + 1) (n + 2) : n^{3} + 3 n^{2} + 2 n

= \frac{n ^{3} + 3 n ^{2} + 2 n}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{n ^{3} + 3 n ^{2} + 2 n}{3} = \frac{n ^{3}}{3} + \frac{3 n ^{2}}{3} + \frac{2 n}{3}

= \frac{n ^{3}}{3} + \frac{3 n ^{2}}{3} + \frac{2 n}{3}

Divide the numbers:

\frac{3}{3} = 1

= \frac{n ^{3}}{3} + n^{2} + \frac{2 n}{3}

\frac{n ( n + 1 ) ( n + 2 )}{6}

(0.5 x + 0.4 y = 0.125) (1000)

(\frac{6}{7} - x)^{4}

(y^{2} - 2 x y + 6 x) d x + (x^{2} - 2 x y + 2) d y

(a + 2 + \frac{7}{a - 5}) (a - 2 - \frac{5}{a + 2})

What is expand (n(n+1)(n+2))/3 ?
The solution to expand (n(n+1)(n+2))/3 is (n^3)/3+n^2+(2n)/3