What is expand (4+3sin(θ))^2 ?

The solution to expand (4+3sin(θ))^2 is 16+24sin(θ)+9sin^2(θ)

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expand (4+3sin(θ))^2

expand

(4 + 3 sin (θ))^{2}

16 + 24 sin (θ) + 9 sin^{2} (θ)

Solution steps

(4 + 3 sin (θ))^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(4 + 3 sin (θ))^{2} = 4^{2} + 2 \cdot 4 \cdot 3 sin (θ) + (3 sin (θ))^{2}

= 4^{2} + 2 \cdot 4 \cdot 3 sin (θ) + (3 sin (θ))^{2}

Simplify

4^{2} + 2 \cdot 4 \cdot 3 sin (θ) + (3 sin (θ))^{2} : 16 + 24 sin (θ) + 9 sin^{2} (θ)

= 16 + 24 sin (θ) + 9 sin^{2} (θ)

(t + e^{2 t})^{3}

\frac{2 s + 1}{( s ^{2} + 1 ) ( s - 1 ) ( s - 3 )}

ln (\frac{y}{1 - y})

(e^{x} + 3)^{2}

What is expand (4+3sin(θ))^2 ?
The solution to expand (4+3sin(θ))^2 is 16+24sin(θ)+9sin^2(θ)