What is expand (2s+3)/((s+1)(s-1)(2s+1)(s+2)) ?

The solution to expand (2s+3)/((s+1)(s-1)(2s+1)(s+2)) is (2s+3)/(2s^4+5s^3-5s-2)

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expand (2s+3)/((s+1)(s-1)(2s+1)(s+2))

expand

\frac{2 s + 3}{( s + 1 ) ( s - 1 ) ( 2 s + 1 ) ( s + 2 )}

\frac{2 s + 3}{2 s ^{4} + 5 s ^{3} - 5 s - 2}

Solution steps

\frac{2 s + 3}{( s + 1 ) ( s - 1 ) ( 2 s + 1 ) ( s + 2 )}

Expand

(s + 1) (s - 1) (2 s + 1) (s + 2) : 2 s^{4} + 5 s^{3} - 5 s - 2

= \frac{2 s + 3}{2 s ^{4} + 5 s ^{3} - 5 s - 2}

(x + \frac{2}{5}) (x - \frac{1}{5})

t (x) x^{^{''}} + (4 t (x) - 6) x^{^{'}} + 4 x

(x - 3) (x - \frac{1}{2})

5 \cdot (x + 4 y = 14)

y^{''} (x) (3 + \frac{1}{x})^{3}

What is expand (2s+3)/((s+1)(s-1)(2s+1)(s+2)) ?
The solution to expand (2s+3)/((s+1)(s-1)(2s+1)(s+2)) is (2s+3)/(2s^4+5s^3-5s-2)