What is expand b^2(b^{1/2}-b^{1/4}) ?

The solution to expand b^2(b^{1/2}-b^{1/4}) is b^{5/2}-b^{9/4}

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expand b^2(b^{1/2}-b^{1/4})

expand

b^{2} (b^{\frac{1}{2}} - b^{\frac{1}{4}})

b^{\frac{5}{2}} - b^{\frac{9}{4}}

Solution steps

b^{2} (b^{\frac{1}{2}} - b^{\frac{1}{4}})

Apply the distributive law:

a (b - c) = ab - a c

b^{2} (b^{\frac{1}{2}} - b^{\frac{1}{4}}) = b^{2} b^{\frac{1}{2}} - b^{2} b^{\frac{1}{4}}

= b^{2} b^{\frac{1}{2}} - b^{2} b^{\frac{1}{4}}

b^{2} b^{\frac{1}{2}} = b^{\frac{5}{2}}

b^{2} b^{\frac{1}{4}} = b^{\frac{9}{4}}

= b^{\frac{5}{2}} - b^{\frac{9}{4}}

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What is expand b^2(b^{1/2}-b^{1/4}) ?
The solution to expand b^2(b^{1/2}-b^{1/4}) is b^{5/2}-b^{9/4}