What is (8x^2+7)(5x-1/4) ?

The solution to (8x^2+7)(5x-1/4) is ((8x^2+7)(20x-1))/4

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simplify (8x^2+7)(5x-1/4)

simplify

(8 x^{2} + 7) (5 x - \frac{1}{4})

\frac{( 8 x ^{2} + 7 ) ( 20 x - 1 )}{4}

Solution steps

(8 x^{2} + 7) (5 x - \frac{1}{4})

Join

5 x - \frac{1}{4} : \frac{20 x - 1}{4}

= (8 x^{2} + 7) \frac{20 x - 1}{4}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 8 x ^{2} + 7 ) ( 20 x - 1 )}{4}

(1 + e^{i θ})^{2}

(3 x - 2) l e f t (x + 2)

A (6, 2) y B (5, - 4)

(- r cos (x) + v cos (y) + d)^{2}

\frac{4}{x ( x - 1 )}

What is (8x^2+7)(5x-1/4) ?
The solution to (8x^2+7)(5x-1/4) is ((8x^2+7)(20x-1))/4