What is expand-5/1 (x+y=7) ?

The solution to expand-5/1 (x+y=7) is -5x-5y=7

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expand-5/1 (x+y=7)

expand

- \frac{5}{1} (x + y = 7)

- 5 x - 5 y = 7

Solution steps

- \frac{5}{1} (x + y = 7)

= - \frac{5}{1} (x + 7 = y)

Apply the distributive law:

a (b + c) = ab + a c

a = - \frac{5}{1}, b = x, c = y = 7

- \frac{5}{1} x + (- \frac{5}{1}) y = 7

Apply minus-plus rules

+ (- a) = - a

- \frac{5}{1} x - \frac{5}{1} y = 7

Expand

- \frac{5}{1} x - \frac{5}{1} y : - 5 x - 5 y

- 5 x - 5 y = 7

2 (e^{x} + e^{x} x)

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