What is expand e^{2x^2-4x}+e^{2x^2-4x}x(4x-4) ?

The solution to expand e^{2x^2-4x}+e^{2x^2-4x}x(4x-4) is e^{2x^2-4x}+4e^{2x^2-4x}x^2-4e^{2x^2-4x}x

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expand e^{2x^2-4x}+e^{2x^2-4x}x(4x-4)

expand

e^{2 x^{2} - 4 x} + e^{2 x^{2} - 4 x} x (4 x - 4)

e^{2 x^{2} - 4 x} + 4 e^{2 x^{2} - 4 x} x^{2} - 4 e^{2 x^{2} - 4 x} x

Solution steps

e^{2 x^{2} - 4 x} + e^{2 x^{2} - 4 x} x (4 x - 4)

Expand

e^{2 x^{2} - 4 x} x (4 x - 4) : 4 e^{2 x^{2} - 4 x} x^{2} - 4 e^{2 x^{2} - 4 x} x

= e^{2 x^{2} - 4 x} + 4 e^{2 x^{2} - 4 x} x^{2} - 4 e^{2 x^{2} - 4 x} x

6 (x + i y)^{5}

\frac{1}{x ( x + 2 )}

\frac{1}{2} (- \frac{ln ( 5 x )}{2 x ^{2}} - \frac{1}{4 x ^{2}}) + C

t (x) x^{^{''}} - (t (x) + 3) x^{^{'}} + 3 x

(2 x + 3) x^{2} + 3 x

What is expand e^{2x^2-4x}+e^{2x^2-4x}x(4x-4) ?
The solution to expand e^{2x^2-4x}+e^{2x^2-4x}x(4x-4) is e^{2x^2-4x}+4e^{2x^2-4x}x^2-4e^{2x^2-4x}x