What is (3x^2+1/10)(3x^2-1/10) ?

The solution to (3x^2+1/10)(3x^2-1/10) is ((30x^2+1)(30x^2-1))/(100)

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simplify (3x^2+1/10)(3x^2-1/10)

simplify

(3 x^{2} + \frac{1}{10}) (3 x^{2} - \frac{1}{10})

\frac{( 30 x ^{2} + 1 ) ( 30 x ^{2} - 1 )}{100}

Solution steps

(3 x^{2} + \frac{1}{10}) (3 x^{2} - \frac{1}{10})

Join

3 x^{2} + \frac{1}{10} : \frac{30 x ^{2} + 1}{10}

= \frac{30 x ^{2} + 1}{10} (3 x^{2} - \frac{1}{10})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 30 x ^{2} + 1 ) ( 3 x ^{2} - \frac{1}{10} )}{10}

Simplify

(30 x^{2} + 1) (3 x^{2} - \frac{1}{10}) : \frac{( 30 x ^{2} + 1 ) ( 30 x ^{2} - 1 )}{10}

= \frac{\frac{( 30 x ^{2} + 1 ) ( 30 x ^{2} - 1 )}{10}}{10}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 30 x ^{2} + 1 ) ( 30 x ^{2} - 1 )}{10 \cdot 10}

Multiply the numbers:

10 \cdot 10 = 100

= \frac{( 30 x ^{2} + 1 ) ( 30 x ^{2} - 1 )}{100}

sin (2) (x + 30 \circ) + cos (2) (x + 30 \circ)

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4 lo g_{3} (x + 2) - 6 lo g_{3} (12) (x - 1)

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(cos (θ) + i sin (θ))^{7}

What is (3x^2+1/10)(3x^2-1/10) ?
The solution to (3x^2+1/10)(3x^2-1/10) is ((30x^2+1)(30x^2-1))/(100)