What is expand (n(2n-1)(2n+1))/3 ?

The solution to expand (n(2n-1)(2n+1))/3 is (4n^3)/3-n/3

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expand (n(2n-1)(2n+1))/3

expand

\frac{n ( 2 n - 1 ) ( 2 n + 1 )}{3}

\frac{4 n ^{3}}{3} - \frac{n}{3}

Solution steps

\frac{n ( 2 n - 1 ) ( 2 n + 1 )}{3}

Expand

n (2 n - 1) (2 n + 1) : 4 n^{3} - n

= \frac{4 n ^{3} - n}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 n ^{3} - n}{3} = \frac{4 n ^{3}}{3} - \frac{n}{3}

= \frac{4 n ^{3}}{3} - \frac{n}{3}

\frac{x - 2}{( x + 2 ) ( x - 3 )}

\frac{x + 6}{x}

(y - 2)^{2}

\frac{( s - 1 ) ^{3}}{s ^{4}}

\frac{1}{9} (e^{3 x} \cdot 3 x - e^{3 x}) + C

What is expand (n(2n-1)(2n+1))/3 ?
The solution to expand (n(2n-1)(2n+1))/3 is (4n^3)/3-n/3