What is expand 1/9 (e^{3x}*3x-e^{3x})+C ?

The solution to expand 1/9 (e^{3x}*3x-e^{3x})+C is (e^{3x}x)/3-1/9 e^{3x}+C

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expand 1/9 (e^{3x}*3x-e^{3x})+C

expand

\frac{1}{9} (e^{3 x} \cdot 3 x - e^{3 x}) + C

\frac{e ^{3 x} x}{3} - \frac{1}{9} e^{3 x} + C

Solution steps

\frac{1}{9} (e^{3 x} \cdot 3 x - e^{3 x}) + C

= \frac{1}{9} (3 e^{3 x} x - e^{3 x}) + C

Expand

\frac{1}{9} (e^{3 x} \cdot 3 x - e^{3 x}) : \frac{e ^{3 x} x}{3} - \frac{1}{9} e^{3 x}

= \frac{e ^{3 x} x}{3} - \frac{1}{9} e^{3 x} + C

(t - a) H (t - a)

(4 x^{3} + \frac{6}{x ^{3}}) (x^{\frac{3}{2}} - 4 x)

(x - 1) (2 x + 5)

\frac{x + 2}{( x + 1 ) ( x - 2 )}

(2 + \frac{t}{2})^{7}

What is expand 1/9 (e^{3x}*3x-e^{3x})+C ?
The solution to expand 1/9 (e^{3x}*3x-e^{3x})+C is (e^{3x}x)/3-1/9 e^{3x}+C