What is expand sin(t)U(t-pi) ?

The solution to expand sin(t)U(t-pi) is tUsin(t)-piUsin(t)

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expand sin(t)U(t-pi)

expand

sin (t) U (t - π)

t U sin (t) - π U sin (t)

Solution steps

sin (t) U (t - π)

= U sin (t) (t - π)

Apply the distributive law:

a (b - c) = ab - a c

a = sin (t) U, b = t, c = π

= sin (t) U t - sin (t) U π

= t U sin (t) - π U sin (t)

\frac{2 x + 3}{( x - 2 ) ( x + 5 )}

(2 cos (x) + 2 sin (x))^{2}

\frac{2 x ( - x ^{2} - 3 )}{25}

\frac{d ^{2}}{d r d s} ((r (s)) (\frac{1}{r ( s )} + \frac{1}{s}))

(x^{3})^{2}

What is expand sin(t)U(t-pi) ?
The solution to expand sin(t)U(t-pi) is tUsin(t)-piUsin(t)