What is expand (x+4)/((x+2)(x^2+3x+1)) ?

The solution to expand (x+4)/((x+2)(x^2+3x+1)) is (x+4)/(x^3+5x^2+7x+2)

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expand (x+4)/((x+2)(x^2+3x+1))

expand

\frac{x + 4}{( x + 2 ) ( x ^{2} + 3 x + 1 )}

\frac{x + 4}{x ^{3} + 5 x ^{2} + 7 x + 2}

Solution steps

\frac{x + 4}{( x + 2 ) ( x ^{2} + 3 x + 1 )}

Expand

(x + 2) (x^{2} + 3 x + 1) : x^{3} + 5 x^{2} + 7 x + 2

= \frac{x + 4}{x ^{3} + 5 x ^{2} + 7 x + 2}

(4 - 4 sin (θ))^{2}

(1 - x) x

(1 + x 6)^{2}

(\frac{1}{2} - \frac{x}{3}) x^{2} e^{2 x}

6.9 (e^{- 0.24 t} - 0.24 e^{- 0.24 t} t)

What is expand (x+4)/((x+2)(x^2+3x+1)) ?
The solution to expand (x+4)/((x+2)(x^2+3x+1)) is (x+4)/(x^3+5x^2+7x+2)