What is expand f(2u+v,v-u) ?

The solution to expand f(2u+v,v-u) is 2fu+fv,v-fu

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expand f(2u+v,v-u)

expand

f (2 u + v, v - u)

2 f u + f v, v - f u

Solution steps

f (2 u + v, v - u)

= f (2 u +, vv - u)

Distribute parentheses

= f \cdot 2 u + f v, v + f (- u)

Apply minus-plus rules

+ (- a) = - a

= 2 f u + f v, v - f u

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\frac{( x + 3 ) ( 2 x - 1 )}{( 2 x + 1 ) ^{2}}

(x - \frac{2}{x ^{2}})^{9}

6 (11 + 7)