What is expand (x^2-1/(4x^2))^2 ?

The solution to expand (x^2-1/(4x^2))^2 is (16x^8-8x^4+1)/(16x^4)

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expand (x^2-1/(4x^2))^2

expand

(x^{2} - \frac{1}{4 x ^{2}})^{2}

\frac{16 x ^{8} - 8 x ^{4} + 1}{16 x ^{4}}

Solution steps

(x^{2} - \frac{1}{4 x ^{2}})^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(x^{2} - \frac{1}{4 x ^{2}})^{2} = (x^{2})^{2} - 2 x^{2} \frac{1}{4 x ^{2}} + (\frac{1}{4 x ^{2}})^{2}

= (x^{2})^{2} - 2 x^{2} \frac{1}{4 x ^{2}} + (\frac{1}{4 x ^{2}})^{2}

Simplify

(x^{2})^{2} - 2 x^{2} \frac{1}{4 x ^{2}} + (\frac{1}{4 x ^{2}})^{2} : \frac{16 x ^{8} - 8 x ^{4} + 1}{16 x ^{4}}

= \frac{16 x ^{8} - 8 x ^{4} + 1}{16 x ^{4}}

\frac{π ( 2 ln ( 2 ) + 1 )}{4}

(\frac{C}{2} - \frac{D}{3}) D^{2}

\frac{d}{d r ( T )} ((E (r, T)) (10 - 10 T (b^{- 0.14 r (T)})))

(x - i y + 1)^{3}

\frac{x ^{2} ( x ^{2} - 3 )}{( x ^{2} - 1 ) ^{2}}

What is expand (x^2-1/(4x^2))^2 ?
The solution to expand (x^2-1/(4x^2))^2 is (16x^8-8x^4+1)/(16x^4)