What is ((x^2y^3)/3-6)((x^2y^3)/3+8) ?

The solution to ((x^2y^3)/3-6)((x^2y^3)/3+8) is ((-18+x^2y^3)(24+x^2y^3))/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((x^2y^3)/3-6)((x^2y^3)/3+8)

simplify

(\frac{x ^{2} y ^{3}}{3} - 6) (\frac{x ^{2} y ^{3}}{3} + 8)

\frac{( - 18 + x ^{2} y ^{3} ) ( 24 + x ^{2} y ^{3} )}{9}

Solution steps

(\frac{x ^{2} y ^{3}}{3} - 6) (\frac{x ^{2} y ^{3}}{3} + 8)

Join

\frac{x ^{2} y ^{3}}{3} - 6 : \frac{- 18 + x ^{2} y ^{3}}{3}

= \frac{- 18 + x ^{2} y ^{3}}{3} (\frac{x ^{2} y ^{3}}{3} + 8)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - 18 + x ^{2} y ^{3} ) ( \frac{x ^{2} y ^{3}}{3} + 8 )}{3}

Simplify

(- 18 + x^{2} y^{3}) (\frac{x ^{2} y ^{3}}{3} + 8) : \frac{( - 18 + x ^{2} y ^{3} ) ( 24 + x ^{2} y ^{3} )}{3}

= \frac{\frac{( - 18 + x ^{2} y ^{3} ) ( 24 + x ^{2} y ^{3} )}{3}}{3}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( - 18 + x ^{2} y ^{3} ) ( 24 + x ^{2} y ^{3} )}{3 \cdot 3}

Multiply the numbers:

3 \cdot 3 = 9

= \frac{( - 18 + x ^{2} y ^{3} ) ( 24 + x ^{2} y ^{3} )}{9}

(0.6 \times \frac{20}{7} + \frac{3}{14}) \times 1.5

(2 + 4 sin (θ))^{2}

(x y - x^{2}) (x y + x^{2})

\frac{1}{2} (arcsin (x) - \frac{1}{2} sin (2 arcsin (x)))

(x x - 1) (1 - x)

What is ((x^2y^3)/3-6)((x^2y^3)/3+8) ?
The solution to ((x^2y^3)/3-6)((x^2y^3)/3+8) is ((-18+x^2y^3)(24+x^2y^3))/9