What is expand ((4x-3)^2)/(16) ?

The solution to expand ((4x-3)^2)/(16) is x^2-(3x)/2+9/16

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expand ((4x-3)^2)/(16)

expand

\frac{( 4 x - 3 ) ^{2}}{16}

x^{2} - \frac{3 x}{2} + \frac{9}{16}

Solution steps

\frac{( 4 x - 3 ) ^{2}}{16}

(4 x - 3)^{2} = 16 x^{2} - 24 x + 9

= \frac{16 x ^{2} - 24 x + 9}{16}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{16 x ^{2} - 24 x + 9}{16} = \frac{16 x ^{2}}{16} - \frac{24 x}{16} + \frac{9}{16}

= \frac{16 x ^{2}}{16} - \frac{24 x}{16} + \frac{9}{16}

Divide the numbers:

\frac{16}{16} = 1

= x^{2} - \frac{24 x}{16} + \frac{9}{16}

Cancel

\frac{24 x}{16} : \frac{3 x}{2}

= x^{2} - \frac{3 x}{2} + \frac{9}{16}

- e^{θ} (- e^{- θ} θ - e^{- θ})

(2 x + y^{2}) d x + 2 x y d y

(4 k - m x) (k b^{2} - \frac{m b ^{2}}{4} x)

\frac{x ^{2} + 1}{( x - 1 ) ^{2}}

(x^{3})^{3}

What is expand ((4x-3)^2)/(16) ?
The solution to expand ((4x-3)^2)/(16) is x^2-(3x)/2+9/16