What is ((4i)/n-1)^2 ?

The solution to ((4i)/n-1)^2 is (n^2-16)/(n^2)-8/n i

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simplify ((4i)/n-1)^2

simplify

(\frac{4 i}{n} - 1)^{2}

\frac{n ^{2} - 16}{n ^{2}} - \frac{8}{n} i

Solution steps

(\frac{4 i}{n} - 1)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(\frac{4 i}{n} - 1)^{2} = (\frac{4 i}{n})^{2} - 2 \cdot \frac{4 i}{n} \cdot 1 + 1^{2}

= (\frac{4 i}{n})^{2} - 2 \cdot \frac{4 i}{n} \cdot 1 + 1^{2}

Simplify

(\frac{4 i}{n})^{2} - 2 \cdot \frac{4 i}{n} \cdot 1 + 1^{2} : \frac{n ^{2} - 16}{n ^{2}} - \frac{8}{n} i

= \frac{n ^{2} - 16}{n ^{2}} - \frac{8}{n} i

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