What is expand x^{2/3}(x-2)^2 ?

The solution to expand x^{2/3}(x-2)^2 is x^{8/3}-4x^{5/3}+x^{2/3}*4

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expand x^{2/3}(x-2)^2

expand

x^{\frac{2}{3}} (x - 2)^{2}

x^{\frac{8}{3}} - 4 x^{\frac{5}{3}} + x^{\frac{2}{3}} \cdot 4

Solution steps

x^{\frac{2}{3}} (x - 2)^{2}

Expand

(x - 2)^{2} : x^{2} - 4 x + 4

= x^{\frac{2}{3}} (x^{2} - 4 x + 4)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

x^{\frac{2}{3}} (x^{2} - 4 x + 4) = x^{\frac{2}{3}} x^{2} + x^{\frac{2}{3}} (- 4 x) + x^{\frac{2}{3}} \cdot 4

= x^{\frac{2}{3}} x^{2} + x^{\frac{2}{3}} (- 4 x) + x^{\frac{2}{3}} \cdot 4

x^{\frac{2}{3}} x^{2} = x^{\frac{8}{3}}

x^{\frac{2}{3}} (- 4 x) = - 4 x^{\frac{5}{3}}

= x^{\frac{8}{3}} - 4 x^{\frac{5}{3}} + x^{\frac{2}{3}} \cdot 4

(1 - x) e^{x} - 1

(3 - 4 y i)^{2}

- 4 (2 x + 5 - 3 x = 35)

(x + 5) (x - 5)

What is expand x^{2/3}(x-2)^2 ?
The solution to expand x^{2/3}(x-2)^2 is x^{8/3}-4x^{5/3}+x^{2/3}*4