What is expand (cos(θ)-x)^2+sin^2(θ) ?

The solution to expand (cos(θ)-x)^2+sin^2(θ) is x^2-2xcos(θ)+1

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expand (cos(θ)-x)^2+sin^2(θ)

expand

(cos (θ) - x)^{2} + sin^{2} (θ)

x^{2} - 2 x cos (θ) + 1

Solution steps

(cos (θ) - x)^{2} + sin^{2} (θ)

Expand

(cos (θ) - x)^{2} : cos^{2} (θ) - 2 x cos (θ) + x^{2}

= cos^{2} (θ) - 2 x cos (θ) + x^{2} + sin^{2} (θ)

Use the Pythagorean identity:

cos^{2} (x) + sin^{2} (x) = 1

= x^{2} - 2 x cos (θ) + 1

\frac{2 x + 1}{x ( x + 1 ) ( x ^{2} + 4 x + 6 )}

(1 + e^{i x})^{2}

- 2 u sin (t) (t - π)

\frac{( x + 3 ) ( x - 2 )}{x - 3}

arctan (f (5 x^{5} - 1))

What is expand (cos(θ)-x)^2+sin^2(θ) ?
The solution to expand (cos(θ)-x)^2+sin^2(θ) is x^2-2xcos(θ)+1