What is (4x^2+9\circ 3x-1)(x) ?

The solution to (4x^2+9\circ 3x-1)(x) is x(4x^2+27\circ x-1)

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simplify (4x^2+9\circ 3x-1)(x)

simplify

(4 x^{2} + 9 \circ 3 x - 1) (x)

x (4 x^{2} + 27 \circ x - 1)

Solution steps

(4 x^{2} + 9 \circ 3 x - 1) (x)

Remove parentheses:

(a) = a

= (4 x^{2} + 9 \circ 3 x - 1) x

Multiply the numbers:

9 \cdot 3 = 27

= x (4 x^{2} + 27 \circ x - 1)

\frac{( 1 - x ^{2} )}{( 1 + x ^{2} ) ^{2}}

\frac{e ^{- π s}}{s ( s ^{2} + 1 )}

- \frac{π ^{2}}{6} (x - \frac{1}{2})

11 sin (2 (t + 13)) - 12

20 (6109 - 83)

What is (4x^2+9\circ 3x-1)(x) ?
The solution to (4x^2+9\circ 3x-1)(x) is x(4x^2+27\circ x-1)