What is (\partial)/(\partial x)((y)(-6/(x^2)+1/6)) ?

The answer to (\partial)/(\partial x)((y)(-6/(x^2)+1/6)) is (12y)/(x^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)((y)(-6/(x^2)+1/6))

\frac{\partial}{\partial x} ((y) (- \frac{6}{x ^{2}} + \frac{1}{6}))

\frac{12 y}{x ^{3}}

Solution steps

\frac{\partial}{\partial x} ((y) (- \frac{6}{x ^{2}} + \frac{1}{6}))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial x} (- \frac{6}{x ^{2}} + \frac{1}{6})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= y (- \frac{\partial}{\partial x} (\frac{6}{x ^{2}}) + \frac{\partial}{\partial x} (\frac{1}{6}))

\frac{\partial}{\partial x} (\frac{6}{x ^{2}}) = - \frac{12}{x ^{3}}

\frac{\partial}{\partial x} (\frac{1}{6}) = 0

= y (- (- \frac{12}{x ^{3}}) + 0)

Simplify

y (- (- \frac{12}{x ^{3}}) + 0) : \frac{12 y}{x ^{3}}

= \frac{12 y}{x ^{3}}

l (3 t^{4} + sin (3 t) + cos (4 t))

\frac{d}{d t} ((s) (tan (t) - t))

(2 - 14) (x - 7)

\frac{300}{( p + 4 ) ^{5}}

(2 - 3 z i)^{2}

What is (\partial)/(\partial x)((y)(-6/(x^2)+1/6)) ?
The answer to (\partial)/(\partial x)((y)(-6/(x^2)+1/6)) is (12y)/(x^3)