What is expand-(2(x^2+4x-4))/((x^2+4)^2) ?

The solution to expand-(2(x^2+4x-4))/((x^2+4)^2) is -(2x^2+8x-8)/(x^4+8x^2+16)

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expand-(2(x^2+4x-4))/((x^2+4)^2)

expand

- \frac{2 ( x ^{2} + 4 x - 4 )}{( x ^{2} + 4 ) ^{2}}

- \frac{2 x ^{2} + 8 x - 8}{x ^{4} + 8 x ^{2} + 16}

Solution steps

- \frac{2 ( x ^{2} + 4 x - 4 )}{( x ^{2} + 4 ) ^{2}}

(x^{2} + 4)^{2} = x^{4} + 8 x^{2} + 16

= - \frac{2 ( x ^{2} + 4 x - 4 )}{x ^{4} + 8 x ^{2} + 16}

Expand

2 (x^{2} + 4 x - 4) : 2 x^{2} + 8 x - 8

= - \frac{2 x ^{2} + 8 x - 8}{x ^{4} + 8 x ^{2} + 16}

\frac{8 x ( 2 x - 1 )}{3 ( 2 x + 1 )}

2 y e^{x y} x + (x^{2} + y^{2}) (e^{x y} x y + e^{x y})

(a cos (θ) + b sin (θ)) (a sin (θ) + b cos (θ))

- \frac{e ^{x y^{2}} x y ^{3} - y}{x ( 1 + 2 e ^{x y^{2}} x y ^{2} )}

(3 + 3 cos (θ))^{3}

What is expand-(2(x^2+4x-4))/((x^2+4)^2) ?
The solution to expand-(2(x^2+4x-4))/((x^2+4)^2) is -(2x^2+8x-8)/(x^4+8x^2+16)