What is expand t^{7/2}(t^2-4t+23) ?

The solution to expand t^{7/2}(t^2-4t+23) is t^{11/2}-4t^{9/2}+t^{7/2}*23

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expand t^{7/2}(t^2-4t+23)

expand

t^{\frac{7}{2}} (t^{2} - 4 t + 23)

t^{\frac{11}{2}} - 4 t^{\frac{9}{2}} + t^{\frac{7}{2}} \cdot 23

Solution steps

t^{\frac{7}{2}} (t^{2} - 4 t + 23)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

t^{\frac{7}{2}} (t^{2} - 4 t + 23) = t^{\frac{7}{2}} t^{2} + t^{\frac{7}{2}} (- 4 t) + t^{\frac{7}{2}} \cdot 23

= t^{\frac{7}{2}} t^{2} + t^{\frac{7}{2}} (- 4 t) + t^{\frac{7}{2}} \cdot 23

t^{\frac{7}{2}} t^{2} = t^{\frac{11}{2}}

t^{\frac{7}{2}} (- 4 t) = - 4 t^{\frac{9}{2}}

= t^{\frac{11}{2}} - 4 t^{\frac{9}{2}} + t^{\frac{7}{2}} \cdot 23

\frac{d}{d x} ((2 x - 3) x^{2}) + (y - 3) y^{2} + 2

x e^{x} (x + 2)

2 (1 - 5)

e^{x} (cos (y) - sin (y))

What is expand t^{7/2}(t^2-4t+23) ?
The solution to expand t^{7/2}(t^2-4t+23) is t^{11/2}-4t^{9/2}+t^{7/2}*23