What is (z+1/4)(z-1/2) ?

The solution to (z+1/4)(z-1/2) is ((4z+1)(2z-1))/8

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simplify (z+1/4)(z-1/2)

simplify

(z + \frac{1}{4}) (z - \frac{1}{2})

\frac{( 4 z + 1 ) ( 2 z - 1 )}{8}

Solution steps

(z + \frac{1}{4}) (z - \frac{1}{2})

Simplify

z + \frac{1}{4} : \frac{4 z + 1}{4}

= \frac{4 z + 1}{4} (z - \frac{1}{2})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 4 z + 1 ) ( z - \frac{1}{2} )}{4}

Simplify

(4 z + 1) (z - \frac{1}{2}) : \frac{( 4 z + 1 ) ( z \cdot 2 - 1 )}{2}

= \frac{\frac{( 4 z + 1 ) ( z \cdot 2 - 1 )}{2}}{4}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 4 z + 1 ) ( z \cdot 2 - 1 )}{2 \cdot 4}

Multiply the numbers:

2 \cdot 4 = 8

= \frac{( 4 z + 1 ) ( z \cdot 2 - 1 )}{8}

= \frac{( 4 z + 1 ) ( 2 z - 1 )}{8}

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