What is expand (4e^{-3t})/((s-3)(s+1)) ?

The solution to expand (4e^{-3t})/((s-3)(s+1)) is (4e^{-3t})/(s^2-2s-3)

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expand (4e^{-3t})/((s-3)(s+1))

expand

\frac{4 e ^{- 3 t}}{( s - 3 ) ( s + 1 )}

\frac{4 e ^{- 3 t}}{s ^{2} - 2 s - 3}

Solution steps

\frac{4 e ^{- 3 t}}{( s - 3 ) ( s + 1 )}

Expand

(s - 3) (s + 1) : s^{2} - 2 s - 3

= \frac{4 e ^{- 3 t}}{s ^{2} - 2 s - 3}

(2 x + \frac{1}{x ^{2}}) (5 - x) (2 x^{5} + 1)^{3}

\frac{2 ( - 4 x - 12 )}{x ^{2} - 12 x + 36}

\frac{3 ( 15 + 7 5 )}{4}

\frac{2 ( 7 \cdot 7 ^{\frac{1}{2}} - 3 \cdot 3 ^{\frac{1}{2}} )}{9 \cdot 3 ^{\frac{1}{2}}}

P (- 1, - 1) y C (3, 5)

What is expand (4e^{-3t})/((s-3)(s+1)) ?
The solution to expand (4e^{-3t})/((s-3)(s+1)) is (4e^{-3t})/(s^2-2s-3)