What is (x/5+1)(x/5-1) ?

The solution to (x/5+1)(x/5-1) is ((5+x)(-5+x))/(25)

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simplify (x/5+1)(x/5-1)

simplify

(\frac{x}{5} + 1) (\frac{x}{5} - 1)

\frac{( 5 + x ) ( - 5 + x )}{25}

Solution steps

(\frac{x}{5} + 1) (\frac{x}{5} - 1)

Join

\frac{x}{5} + 1 : \frac{5 + x}{5}

= \frac{5 + x}{5} (\frac{x}{5} - 1)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 5 + x ) ( \frac{x}{5} - 1 )}{5}

Simplify

(5 + x) (\frac{x}{5} - 1) : \frac{( 5 + x ) ( - 5 + x )}{5}

= \frac{\frac{( 5 + x ) ( - 5 + x )}{5}}{5}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 5 + x ) ( - 5 + x )}{5 \cdot 5}

Multiply the numbers:

5 \cdot 5 = 25

= \frac{( 5 + x ) ( - 5 + x )}{25}

I n (\frac{x ^{4} y}{3 z ^{5}})

(3 - 2)^{6}

\frac{2 ( 4 + 79 )}{3}

(3 - x + 5) (3 + x + 5)

(2 x^{14} + \frac{1}{x ^{3}})^{10}