What is expand ((x^2+1+2x)(x-1))/2 ?

The solution to expand ((x^2+1+2x)(x-1))/2 is (x^3)/2+(x^2)/2-x/2-1/2

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expand ((x^2+1+2x)(x-1))/2

expand

\frac{( x ^{2} + 1 + 2 x ) ( x - 1 )}{2}

\frac{x ^{3}}{2} + \frac{x ^{2}}{2} - \frac{x}{2} - \frac{1}{2}

Solution steps

\frac{( x ^{2} + 1 + 2 x ) ( x - 1 )}{2}

Expand

(x^{2} + 1 + 2 x) (x - 1) : x^{3} + x^{2} - x - 1

= \frac{x ^{3} + x ^{2} - x - 1}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} + x ^{2} - x - 1}{2} = \frac{x ^{3}}{2} + \frac{x ^{2}}{2} - \frac{x}{2} - \frac{1}{2}

= \frac{x ^{3}}{2} + \frac{x ^{2}}{2} - \frac{x}{2} - \frac{1}{2}

(x + 2) (x - 3)

53 (22 + 4)

(2 x) l e f t (2 x + 7)

\frac{11 x + 7}{( 2 x - 1 ) ( x + 2 ) ^{2}}

\frac{- 4 x + 6}{( x - 2 ) ^{2} ( x - 1 ) ^{2}}

What is expand ((x^2+1+2x)(x-1))/2 ?
The solution to expand ((x^2+1+2x)(x-1))/2 is (x^3)/2+(x^2)/2-x/2-1/2