What is expand 6(x-3=x+2+x) ?

The solution to expand 6(x-3=x+2+x) is 6x-18=7x+12

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expand 6(x-3=x+2+x)

expand

6 (x - 3 = x + 2 + x)

6 x - 18 = 7 x + 12

Solution steps

6 (x - 3 = x + 2 + x)

Distribute parentheses

= 6 x + 6 (- 3 = x) + 6 \cdot 2 + 6 x

Apply minus-plus rules

+ (- a) = - a

6 x - 6 \cdot 3 = x + 6 \cdot 2 + 6 x

Simplify

6 x - 6 \cdot 3 = x + 6 \cdot 2 + 6 x : 6 x - 18 = 7 x + 12

6 x - 18 = 7 x + 12

\frac{( n + 1 ) ^{2}}{n ^{2} + 1}

(2 u + \frac{2}{3} v)^{2}

\frac{x ^{3} + 2 x ^{2} + 3 x + 2}{( x ^{2} + 1 ) ^{2}}

\frac{( 2 - x ) \times ( - x + 3 )}{( x ^{2} + x + 1 ) ( x - 5 )}

(2 x + \frac{3}{x})^{4}

What is expand 6(x-3=x+2+x) ?
The solution to expand 6(x-3=x+2+x) is 6x-18=7x+12