What is ((2x)/3+2/5)((2x)/3-2/5) ?

The solution to ((2x)/3+2/5)((2x)/3-2/5) is ((10x+6)(10x-6))/(225)

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simplify ((2x)/3+2/5)((2x)/3-2/5)

simplify

(\frac{2 x}{3} + \frac{2}{5}) (\frac{2 x}{3} - \frac{2}{5})

\frac{( 10 x + 6 ) ( 10 x - 6 )}{225}

Solution steps

(\frac{2 x}{3} + \frac{2}{5}) (\frac{2 x}{3} - \frac{2}{5})

Join

\frac{2 x}{3} + \frac{2}{5} : \frac{10 x + 6}{15}

= \frac{10 x + 6}{15} (\frac{2 x}{3} - \frac{2}{5})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 10 x + 6 ) ( \frac{2 x}{3} - \frac{2}{5} )}{15}

Simplify

(10 x + 6) (\frac{2 x}{3} - \frac{2}{5}) : \frac{( 10 x + 6 ) ( 10 x - 6 )}{15}

= \frac{\frac{( 10 x + 6 ) ( 10 x - 6 )}{15}}{15}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 10 x + 6 ) ( 10 x - 6 )}{15 \cdot 15}

Multiply the numbers:

15 \cdot 15 = 225

= \frac{( 10 x + 6 ) ( 10 x - 6 )}{225}

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(x - \frac{1}{2}) (x + 3)

A (3, 3) B (- 4, - 4)

What is ((2x)/3+2/5)((2x)/3-2/5) ?
The solution to ((2x)/3+2/5)((2x)/3-2/5) is ((10x+6)(10x-6))/(225)