What is expand ((4-x^2)^3)/3 ?

The solution to expand ((4-x^2)^3)/3 is -(x^6)/3+4x^4-16x^2+64/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((4-x^2)^3)/3

expand

\frac{( 4 - x ^{2} ) ^{3}}{3}

- \frac{x ^{6}}{3} + 4 x^{4} - 16 x^{2} + \frac{64}{3}

Solution steps

\frac{( 4 - x ^{2} ) ^{3}}{3}

(4 - x^{2})^{3} = 64 - 48 x^{2} + 12 x^{4} - x^{6}

= \frac{64 - 48 x ^{2} + 12 x ^{4} - x ^{6}}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{64 - 48 x ^{2} + 12 x ^{4} - x ^{6}}{3} = \frac{64}{3} - \frac{48 x ^{2}}{3} + \frac{12 x ^{4}}{3} - \frac{x ^{6}}{3}

= \frac{64}{3} - \frac{48 x ^{2}}{3} + \frac{12 x ^{4}}{3} - \frac{x ^{6}}{3}

Divide the numbers:

\frac{48}{3} = 16

= \frac{64}{3} - 16 x^{2} + \frac{12 x ^{4}}{3} - \frac{x ^{6}}{3}

Divide the numbers:

\frac{12}{3} = 4

= \frac{64}{3} - 16 x^{2} + 4 x^{4} - \frac{x ^{6}}{3}

Rewrite in standard form

= - \frac{x ^{6}}{3} + 4 x^{4} - 16 x^{2} + \frac{64}{3}

(2, 14) y (- 1, - 7)

e^{(- 2 + 3 i) t}

(cos (a) + cos (b))^{2} + (sin (a) - sin (b))^{2}

\frac{d ^{2}}{d x ^{2}} ((y) (a x^{2} + b x + c x e^{- 3 x}))

\frac{( x - 2 ) ( x - 4 )}{3}

What is expand ((4-x^2)^3)/3 ?
The solution to expand ((4-x^2)^3)/3 is -(x^6)/3+4x^4-16x^2+64/3