What is expand (e^{-5s}(2s+3))/((s^2+2s+5)(s)) ?

The solution to expand (e^{-5s}(2s+3))/((s^2+2s+5)(s)) is (2e^{-5s}s+3e^{-5s})/(s^3+2s^2+5s)

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expand (e^{-5s}(2s+3))/((s^2+2s+5)(s))

expand

\frac{e ^{- 5 s} ( 2 s + 3 )}{( s ^{2} + 2 s + 5 ) ( s )}

\frac{2 e ^{- 5 s} s + 3 e ^{- 5 s}}{s ^{3} + 2 s ^{2} + 5 s}

Solution steps

\frac{e ^{- 5 s} ( 2 s + 3 )}{( s ^{2} + 2 s + 5 ) ( s )}

Remove parentheses:

(a) = a

= \frac{e ^{- 5 s} ( 2 s + 3 )}{( s ^{2} + 2 s + 5 ) s}

Expand

(s^{2} + 2 s + 5) s : s^{3} + 2 s^{2} + 5 s

= \frac{e ^{- 5 s} ( 2 s + 3 )}{s ^{3} + 2 s ^{2} + 5 s}

Expand

e^{- 5 s} (2 s + 3) : 2 e^{- 5 s} s + 3 e^{- 5 s}

= \frac{2 e ^{- 5 s} s + 3 e ^{- 5 s}}{s ^{3} + 2 s ^{2} + 5 s}

(4 y^{3} - 8 y^{2} - 3 x + 1) (y + \frac{1}{2})

f (x) = \frac{3 ( x ^{2} + 1 ) ^{2} ( x ^{2} - 2 x - 1 )}{( x - 1 ) ^{4}}

(x + 3 x^{3} sin (y)) d x + x^{4} cos (y) d y

cos (x) (sec (x) + tan (x))

(2 - 3 x)^{2}

What is expand (e^{-5s}(2s+3))/((s^2+2s+5)(s)) ?
The solution to expand (e^{-5s}(2s+3))/((s^2+2s+5)(s)) is (2e^{-5s}s+3e^{-5s})/(s^3+2s^2+5s)