What is expand 2x^2+3y^3-(x^3+2xy^2)y'(x) ?

The solution to expand 2x^2+3y^3-(x^3+2xy^2)y'(x) is 2x^2+3y^3-x^3y'(x)-2xy'(x)y^2

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expand 2x^2+3y^3-(x^3+2xy^2)y'(x)

expand

2 x^{2} + 3 y^{3} - (x^{3} + 2 x y^{2}) y^{'} (x)

2 x^{2} + 3 y^{3} - x^{3} y' (x) - 2 x y' (x) y^{2}

Solution steps

2 x^{2} + 3 y^{3} - (x^{3} + 2 x y^{2}) y^{'} (x)

Expand

- y^{'} (x) (x^{3} + 2 x y^{2}) : - x^{3} y^{'} (x) - 2 x y^{'} (x) y^{2}

= 2 x^{2} + 3 y^{3} - x^{3} y^{'} (x) - 2 x y^{'} (x) y^{2}

(1 - x^{\frac{1}{4}})^{2}

x - 2^{2}

(x - 3 y)^{2}

- \frac{1}{3} x (x - 2) (x - 8) (x - 14)

\frac{1}{( t + 1 ) ^{2}}

What is expand 2x^2+3y^3-(x^3+2xy^2)y'(x) ?
The solution to expand 2x^2+3y^3-(x^3+2xy^2)y'(x) is 2x^2+3y^3-x^3y'(x)-2xy'(x)y^2