What is expand-1/3 x(x-2)(x-8)(x-14) ?

The solution to expand-1/3 x(x-2)(x-8)(x-14) is -(x^4)/3+8x^3-52x^2+(224x)/3

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expand-1/3 x(x-2)(x-8)(x-14)

expand

- \frac{1}{3} x (x - 2) (x - 8) (x - 14)

- \frac{x ^{4}}{3} + 8 x^{3} - 52 x^{2} + \frac{224 x}{3}

Solution steps

- \frac{1}{3} x (x - 2) (x - 8) (x - 14)

Expand

- \frac{1}{3} x (x - 2) (x - 8) (x - 14) : - \frac{1}{3} x (x^{2} - 10 x + 16) (x - 14)

= - \frac{1}{3} x (x^{2} - 10 x + 16) (x - 14)

Expand

- \frac{1}{3} x (x - 14) : - \frac{x ^{2}}{3} + \frac{14 x}{3}

= (- \frac{x ^{2}}{3} + \frac{14 x}{3}) (x^{2} - 10 x + 16)

Distribute parentheses

= - \frac{x ^{2}}{3} x^{2} - \frac{x ^{2}}{3} (- 10 x) - \frac{x ^{2}}{3} \cdot 16 + \frac{14 x}{3} x^{2} + \frac{14 x}{3} (- 10 x) + \frac{14 x}{3} \cdot 16

Simplify

- \frac{x ^{2}}{3} x^{2} - \frac{x ^{2}}{3} (- 10 x) - \frac{x ^{2}}{3} \cdot 16 + \frac{14 x}{3} x^{2} + \frac{14 x}{3} (- 10 x) + \frac{14 x}{3} \cdot 16 : - \frac{x ^{4}}{3} + 8 x^{3} - 52 x^{2} + \frac{224 x}{3}

= - \frac{x ^{4}}{3} + 8 x^{3} - 52 x^{2} + \frac{224 x}{3}

\frac{1}{( t + 1 ) ^{2}}

24 (\frac{4}{5} x - \frac{3}{5} y) (\frac{3}{5} x + \frac{4}{5} y)

\frac{1}{( s - i ) ^{3}} + \frac{1}{( s + i ) ^{3}}

\frac{1}{( s + 5 ) ( s - 4 )}

(4 x^{3} + 5) \cdot (x^{4} + 5 x)^{\frac{1}{2}}

What is expand-1/3 x(x-2)(x-8)(x-14) ?
The solution to expand-1/3 x(x-2)(x-8)(x-14) is -(x^4)/3+8x^3-52x^2+(224x)/3