What is expand (3(2xy-x^2\frac{dy)/(dx))}{2y^2} ?

The solution to expand (3(2xy-x^2\frac{dy)/(dx))}{2y^2} is (3x)/y-(3x^2\frac{dy)/(dx)}{2y^2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (3(2xy-x^2\frac{dy)/(dx))}{2y^2}

expand

\frac{3 ( 2 x y - x ^{2} \frac{d y}{d x} )}{2 y ^{2}}

\frac{3 x}{y} - \frac{3 x ^{2} \frac{d y}{d x}}{2 y ^{2}}

Solution steps

\frac{3 ( 2 x y - x ^{2} \frac{d y}{d x} )}{2 y ^{2}}

Expand

3 (2 x y - x^{2} \frac{d y}{d x}) : 6 x y - 3 x^{2} \frac{d y}{d x}

= \frac{6 x y - 3 x ^{2} \frac{d y}{d x}}{2 y ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 x y - 3 x ^{2} \frac{d y}{d x}}{2 y ^{2}} = \frac{6 x y}{2 y ^{2}} - \frac{3 x ^{2} \frac{d y}{d x}}{2 y ^{2}}

= \frac{6 x y}{2 y ^{2}} - \frac{3 x ^{2} \frac{d y}{d x}}{2 y ^{2}}

Cancel

\frac{6 x y}{2 y ^{2}} : \frac{3 x}{y}

= \frac{3 x}{y} - \frac{3 x ^{2} \frac{d y}{d x}}{2 y ^{2}}

(1 + cot (\frac{5 π}{18})) l e f t (1 + tan (\frac{π}{36}))

D x (\frac{1}{3} sec^{3} (2 x) - sec (2 x))

(u - 1)^{2} u

\frac{5 ( x + 3 )}{3 x}

(x + 3) \cdot (x^{2} - 4)

What is expand (3(2xy-x^2\frac{dy)/(dx))}{2y^2} ?
The solution to expand (3(2xy-x^2\frac{dy)/(dx))}{2y^2} is (3x)/y-(3x^2\frac{dy)/(dx)}{2y^2}