What is expand (s+1+i)(s+1-i) ?

The solution to expand (s+1+i)(s+1-i) is s^2+2s+2

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expand (s+1+i)(s+1-i)

expand

(s + 1 + i) (s + 1 - i)

s^{2} + 2 s + 2

Solution steps

(s + 1 + i) (s + 1 - i)

Distribute parentheses

= ss + s \cdot 1 + s (- i) + 1 \cdot s + 1 \cdot 1 + 1 \cdot (- i) + i s + i 1 + i (- i)

Simplify

ss + s \cdot 1 + s (- i) + 1 \cdot s + 1 \cdot 1 + 1 \cdot (- i) + i s + i 1 + i (- i) : s^{2} + 2 s + 2

= s^{2} + 2 s + 2

(e^{x}) (x^{2} e^{x} - x)

x (\frac{2 + x}{- 15} - \frac{x - 4}{3} = 4)

\frac{( x ^{2} - a ^{2} )}{( x + b ) ( x - c )}

e^{x} (1 + e^{x})^{2}

(6 - 3 x + 3)^{2}

What is expand (s+1+i)(s+1-i) ?
The solution to expand (s+1+i)(s+1-i) is s^2+2s+2