What is expand (x^2+4)/((x-3)(x-5)) ?

The solution to expand (x^2+4)/((x-3)(x-5)) is (x^2+4)/(x^2-8x+15)

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expand (x^2+4)/((x-3)(x-5))

expand

\frac{x ^{2} + 4}{( x - 3 ) ( x - 5 )}

\frac{x ^{2} + 4}{x ^{2} - 8 x + 15}

Solution steps

\frac{x ^{2} + 4}{( x - 3 ) ( x - 5 )}

Expand

(x - 3) (x - 5) : x^{2} - 8 x + 15

= \frac{x ^{2} + 4}{x ^{2} - 8 x + 15}

5 (2 x + 4 - x + 10 = 3 x + 3)

(x y^{2} + x) d y

\frac{5 x ^{2} - 2 x + 12}{( x + 2 ) ( x - 1 ) ^{2}}

(1 - 2 i)^{9} 6

(3 x^{2} + 4 e^{y}) d x + (2 R x e^{y} + 5) d y

What is expand (x^2+4)/((x-3)(x-5)) ?
The solution to expand (x^2+4)/((x-3)(x-5)) is (x^2+4)/(x^2-8x+15)