What is expand 1/(2sqrt(3x^2+y))(6x) ?

The solution to expand 1/(2sqrt(3x^2+y))(6x) is (3xsqrt(3x^2+y))/(3x^2+y)

Popular >

expand 1/(2sqrt(3x^2+y))(6x)

expand

\frac{1}{2 3 x ^{2} + y} (6 x)

\frac{3 x 3 x ^{2} + y}{3 x ^{2} + y}

Solution steps

\frac{1}{2 3 x ^{2} + y} (6 x)

Remove parentheses:

(a) = a

= \frac{1}{2 3 x ^{2} + y} \cdot 6 x

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 6 x}{2 3 x ^{2} + y}

Multiply the numbers:

1 \cdot 6 = 6

= \frac{6 x}{2 3 x ^{2} + y}

Divide the numbers:

\frac{6}{2} = 3

= \frac{3 x}{3 x ^{2} + y}

Rationalize

\frac{3 x}{3 x ^{2} + y} : \frac{3 x 3 x ^{2} + y}{3 x ^{2} + y}

= \frac{3 x 3 x ^{2} + y}{3 x ^{2} + y}

e^{2 x} \cdot (e^{- 2 x} x + \frac{1}{2} e^{- 2 x} + c)

x^{2} 1 + (2 x)^{2}

(- 2, 3, 4) y (2, - 3, 5)

(x - \frac{5}{2}) \cdot (x + \frac{5}{2})

\frac{9 ( - e ^{2} + 1 )}{10 ( e ^{2} + 9 )} + 1

What is expand 1/(2sqrt(3x^2+y))(6x) ?
The solution to expand 1/(2sqrt(3x^2+y))(6x) is (3xsqrt(3x^2+y))/(3x^2+y)