What is expand 2cos(x)+(2x-pi/2)sin(x) ?

The solution to expand 2cos(x)+(2x-pi/2)sin(x) is 2cos(x)+2xsin(x)-pi/2 sin(x)

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expand 2cos(x)+(2x-pi/2)sin(x)

expand

2 cos (x) + (2 x - \frac{π}{2}) sin (x)

2 cos (x) + 2 x sin (x) - \frac{π}{2} sin (x)

Solution steps

2 cos (x) + (2 x - \frac{π}{2}) sin (x)

= 2 cos (x) + sin (x) (2 x - \frac{π}{2})

Expand

sin (x) (2 x - \frac{π}{2}) : 2 x sin (x) - \frac{π}{2} sin (x)

= 2 cos (x) + 2 x sin (x) - \frac{π}{2} sin (x)

(4 + 4 cos (x))^{2}

2 - \frac{1}{4} sin (2) (x - \frac{π}{4})

(- z^{2} + 2 z - 1)^{8}

(a + 7)^{2}

(4 x^{\frac{1}{2}} + 5) (4 x^{\frac{1}{2}} - 5)

What is expand 2cos(x)+(2x-pi/2)sin(x) ?
The solution to expand 2cos(x)+(2x-pi/2)sin(x) is 2cos(x)+2xsin(x)-pi/2 sin(x)