What is expand 1/((x-1)(x-2)(x-3)) ?

The solution to expand 1/((x-1)(x-2)(x-3)) is 1/(x^3-6x^2+11x-6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 1/((x-1)(x-2)(x-3))

expand

\frac{1}{( x - 1 ) ( x - 2 ) ( x - 3 )}

\frac{1}{x ^{3} - 6 x ^{2} + 11 x - 6}

Solution steps

\frac{1}{( x - 1 ) ( x - 2 ) ( x - 3 )}

Expand

(x - 1) (x - 2) (x - 3) : x^{3} - 6 x^{2} + 11 x - 6

= \frac{1}{x ^{3} - 6 x ^{2} + 11 x - 6}

\frac{x ^{3} + 1}{( x - 1 ) ^{2}}

a (e^{b x^{2}} + 2 b e^{b x^{2}} x^{2})

2 (3 s + 1) (s + \frac{1}{14})

det (- x (x + 2) (x + 3))

(1 + ln (x) + \frac{y}{x}) d x

What is expand 1/((x-1)(x-2)(x-3)) ?
The solution to expand 1/((x-1)(x-2)(x-3)) is 1/(x^3-6x^2+11x-6)