What is expand (x(18-x)(36-x))/6 ?

The solution to expand (x(18-x)(36-x))/6 is (x^3)/6-9x^2+108x

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expand (x(18-x)(36-x))/6

expand

\frac{x ( 18 - x ) ( 36 - x )}{6}

\frac{x ^{3}}{6} - 9 x^{2} + 108 x

Solution steps

\frac{x ( 18 - x ) ( 36 - x )}{6}

Expand

x (18 - x) (36 - x) : 648 x - 54 x^{2} + x^{3}

= \frac{648 x - 54 x ^{2} + x ^{3}}{6}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{648 x - 54 x ^{2} + x ^{3}}{6} = \frac{648 x}{6} - \frac{54 x ^{2}}{6} + \frac{x ^{3}}{6}

= \frac{648 x}{6} - \frac{54 x ^{2}}{6} + \frac{x ^{3}}{6}

Divide the numbers:

\frac{648}{6} = 108

= 108 x - \frac{54 x ^{2}}{6} + \frac{x ^{3}}{6}

Divide the numbers:

\frac{54}{6} = 9

= 108 x - 9 x^{2} + \frac{x ^{3}}{6}

Rewrite in standard form

= \frac{x ^{3}}{6} - 9 x^{2} + 108 x

- 30 t + 780 (1 - e^{- \frac{t}{3}})

(sin (x) - cos (x))^{2}

\frac{1}{π ( a ^{2} - b ^{2} )} + \frac{4 b \cdot c}{π ( a ^{4} - b ^{4} )}

(1.02)^{3}

\frac{( 2 - x ) ^{3}}{6}

What is expand (x(18-x)(36-x))/6 ?
The solution to expand (x(18-x)(36-x))/6 is (x^3)/6-9x^2+108x