What is expand-((t-12)^2)/(10) ?

The solution to expand-((t-12)^2)/(10) is -(t^2}{10}+\frac{12t)/5-72/5

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expand-((t-12)^2)/(10)

expand

- \frac{( t - 12 ) ^{2}}{10}

- \frac{t ^{2}}{10} + \frac{12 t}{5} - \frac{72}{5}

Solution steps

- \frac{( t - 12 ) ^{2}}{10}

(t - 12)^{2} = t^{2} - 24 t + 144

= - \frac{t ^{2} - 24 t + 144}{10}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{t ^{2} - 24 t + 144}{10} = - (\frac{t ^{2}}{10}) - (- \frac{24 t}{10}) - (\frac{144}{10})

= - (\frac{t ^{2}}{10}) - (- \frac{24 t}{10}) - (\frac{144}{10})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{t ^{2}}{10} + \frac{24 t}{10} - \frac{144}{10}

Cancel

\frac{24 t}{10} : \frac{12 t}{5}

= - \frac{t ^{2}}{10} + \frac{12 t}{5} - \frac{144}{10}

Cancel

\frac{144}{10} : \frac{72}{5}

= - \frac{t ^{2}}{10} + \frac{12 t}{5} - \frac{72}{5}

\frac{2 + x ^{3}}{x ^{3} ( x ^{2} + 9 )}

\frac{x + 1}{( x - 3 ) ( x + 4 )}

(2 x^{\frac{2}{3}} - x) (x^{3} + 3 x)

(2 + x) (3 - x)

ln (x + 4)

What is expand-((t-12)^2)/(10) ?
The solution to expand-((t-12)^2)/(10) is -(t^2}{10}+\frac{12t)/5-72/5