What is (\partial)/(\partial x)((z)(x^2+3xy+y^2)) ?

The answer to (\partial)/(\partial x)((z)(x^2+3xy+y^2)) is z(2x+3y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)((z)(x^2+3xy+y^2))

\frac{\partial}{\partial x} ((z) (x^{2} + 3 x y + y^{2}))

z (2 x + 3 y)

Solution steps

\frac{\partial}{\partial x} ((z) (x^{2} + 3 x y + y^{2}))

Treat

z, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z \frac{\partial}{\partial x} (x^{2} + 3 x y + y^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= z (\frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (3 x y) + \frac{\partial}{\partial x} (y^{2}))

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (3 x y) = 3 y

\frac{\partial}{\partial x} (y^{2}) = 0

= z (2 x + 3 y + 0)

Simplify

= z (2 x + 3 y)

k q (\frac{1}{x} - \frac{1}{b d})

\frac{n ( n + 1 ) ( 2 n + 1 )}{6} + 3 (\frac{n ( n + 1 )}{2})

(1, - i) (2, - 1)

\frac{e ^{2 s}}{s ^{2} ( s - 1 )}

(12 - x) ln (x + 8)

What is (\partial)/(\partial x)((z)(x^2+3xy+y^2)) ?
The answer to (\partial)/(\partial x)((z)(x^2+3xy+y^2)) is z(2x+3y)