What is kq(1/x-1/(bd)) ?

The solution to kq(1/x-1/(bd)) is (kq(bd-x))/(bdx)

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simplify kq(1/x-1/(bd))

simplify

k q (\frac{1}{x} - \frac{1}{b d})

\frac{k q ( b d - x )}{b d x}

Solution steps

k q (\frac{1}{x} - \frac{1}{b d})

Join

\frac{1}{x} - \frac{1}{b d} : \frac{b d - x}{b d x}

= k q \frac{b d - x}{b d x}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{k q ( b d - x )}{b d x}

\frac{n ( n + 1 ) ( 2 n + 1 )}{6} + 3 (\frac{n ( n + 1 )}{2})

(1, - i) (2, - 1)

\frac{e ^{2 s}}{s ^{2} ( s - 1 )}

(12 - x) ln (x + 8)

\frac{2 s + 1}{( s - 3 ) ( s ^{2} + 2 )}