What is (x+2)(x+5/4)(x+1/2)(x-1/4)(x-1) ?

The solution to (x+2)(x+5/4)(x+1/2)(x-1/4)(x-1) is ((x+2)(4x+5)(2x+1)(4x-1)(x-1))/(32)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (x+2)(x+5/4)(x+1/2)(x-1/4)(x-1)

simplify

(x + 2) (x + \frac{5}{4}) (x + \frac{1}{2}) (x - \frac{1}{4}) (x - 1)

\frac{( x + 2 ) ( 4 x + 5 ) ( 2 x + 1 ) ( 4 x - 1 ) ( x - 1 )}{32}

Solution steps

(x + 2) (x + \frac{5}{4}) (x + \frac{1}{2}) (x - \frac{1}{4}) (x - 1)

Simplify

x + \frac{5}{4} : \frac{4 x + 5}{4}

= (x + 2) \frac{4 x + 5}{4} (x + \frac{1}{2}) (x - \frac{1}{4}) (x - 1)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x + 2 ) ( 4 x + 5 ) ( x + \frac{1}{2} ) ( x - \frac{1}{4} ) ( x - 1 )}{4}

Simplify

(x + 2) (4 x + 5) (x + \frac{1}{2}) (x - \frac{1}{4}) (x - 1) : \frac{( x + 2 ) ( 4 x + 5 ) ( x \cdot 2 + 1 ) ( x \cdot 4 - 1 ) ( x - 1 )}{8}

= \frac{\frac{( x + 2 ) ( 4 x + 5 ) ( x \cdot 2 + 1 ) ( x \cdot 4 - 1 ) ( x - 1 )}{8}}{4}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( x + 2 ) ( 4 x + 5 ) ( x \cdot 2 + 1 ) ( x \cdot 4 - 1 ) ( x - 1 )}{8 \cdot 4}

Multiply the numbers:

8 \cdot 4 = 32

= \frac{( x + 2 ) ( 4 x + 5 ) ( x \cdot 2 + 1 ) ( x \cdot 4 - 1 ) ( x - 1 )}{32}

= \frac{( x + 2 ) ( 4 x + 5 ) ( 2 x + 1 ) ( 4 x - 1 ) ( x - 1 )}{32}

P (\frac{0.1}{2 , 1}) Q (2, 1, - 3)

\frac{- 3}{4} sec^{3} (\frac{π}{2})

A (2, 7) y B (- 6, - 9)

\frac{( 2 y ^{4} + 2 y ^{2} + 1 ) ( 2 y ^{4} - 2 y ^{2} + 1 ) d y}{4 y ^{4}}

(x - i)^{4}

What is (x+2)(x+5/4)(x+1/2)(x-1/4)(x-1) ?
The solution to (x+2)(x+5/4)(x+1/2)(x-1/4)(x-1) is ((x+2)(4x+5)(2x+1)(4x-1)(x-1))/(32)