What is expand (-xcos^2(y)-xsin^2(y))^2 ?

The solution to expand (-xcos^2(y)-xsin^2(y))^2 is x^2cos^4(y)+2x^2cos^2(y)sin^2(y)+x^2sin^4(y)

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expand (-xcos^2(y)-xsin^2(y))^2

expand

(- x cos^{2} (y) - x sin^{2} (y))^{2}

x^{2} cos^{4} (y) + 2 x^{2} cos^{2} (y) sin^{2} (y) + x^{2} sin^{4} (y)

Solution steps

(- x cos^{2} (y) - x sin^{2} (y))^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(- x cos^{2} (y) - x sin^{2} (y))^{2} = (- x cos^{2} (y))^{2} - 2 (- x cos^{2} (y)) x sin^{2} (y) + (x sin^{2} (y))^{2}

= (- x cos^{2} (y))^{2} - 2 (- x cos^{2} (y)) x sin^{2} (y) + (x sin^{2} (y))^{2}

Simplify

(- x cos^{2} (y))^{2} - 2 (- x cos^{2} (y)) x sin^{2} (y) + (x sin^{2} (y))^{2} : x^{2} cos^{4} (y) + 2 x^{2} cos^{2} (y) sin^{2} (y) + x^{2} sin^{4} (y)

= x^{2} cos^{4} (y) + 2 x^{2} cos^{2} (y) sin^{2} (y) + x^{2} sin^{4} (y)

(3 - cos (t)) \cdot (sin (t))

e^{- 4 (x + h)} - (e^{- 4 x})

\frac{x + 6}{x ( x + 3 )}

(x + \frac{1}{4}) (x - \frac{3}{4})

What is expand (-xcos^2(y)-xsin^2(y))^2 ?
The solution to expand (-xcos^2(y)-xsin^2(y))^2 is x^2cos^4(y)+2x^2cos^2(y)sin^2(y)+x^2sin^4(y)