What is (6-sqrt(2x+1))^2 ?

The solution to (6-sqrt(2x+1))^2 is 2x-12sqrt(2x+1)+37

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simplify (6-sqrt(2x+1))^2

simplify

(6 - 2 x + 1)^{2}

2 x - 12 2 x + 1 + 37

Solution steps

(6 - 2 x + 1)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(6 - 2 x + 1)^{2} = 6^{2} - 2 \cdot 6 2 x + 1 + (2 x + 1)^{2}

= 6^{2} - 2 \cdot 6 2 x + 1 + (2 x + 1)^{2}

Simplify

6^{2} - 2 \cdot 6 2 x + 1 + (2 x + 1)^{2} : 2 x - 12 2 x + 1 + 37

= 2 x - 12 2 x + 1 + 37

\frac{( x + 3 ) ( x - 7 )}{( x + 4 ) ( x - 5 )}

\frac{x + 2}{( x - 4 ) ( x - 2 )}

\frac{4 b ( a b ^{2} - a ^{5} )}{( a ^{4} + b ^{2} ) ^{2}}

\frac{8640 e ^{- 0.96 t}}{( 1 + 3 e ^{- 0.96 t} ) ^{2}}

c (1 - \frac{u ^{2}}{x ^{2}})

What is (6-sqrt(2x+1))^2 ?
The solution to (6-sqrt(2x+1))^2 is 2x-12sqrt(2x+1)+37